Question

Find the HCF of the following number using prime factorization method 90 250 342​

Answer 1

Answer:

Here firstly we have to find the factors of 90, 250, 342 i.e ,

Factors of 90- 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90

Factors of 250 - 1, 2, 5, 10, 25, 50, 125, 250

Factors of 342 - 1, 2, 3, 6, 9, 18, 19, 38, 57, 114, 171, 342

now for the hcf of 90, 250, 342, we have to find the common between the factors of 90, 250, 342 i.e ,

1 , 2

now multiply those factors i.e ,

1 × 2

so the hcf is 2

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