the brakes applied to a car produce an acceleration of 6 m s-2 in the opposite direction to the the motion . If the car takes 2 s to stop after the application of brakes calculate the distance it travels during this time.
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Answer:
12m
Explanation:
Acceleration, a = -6m/s^2
Time, t = 2s
Final velocity, v = 0 (as car comes to rest)
v = u + at
0 = u + (-12)
from here, we get
u = 12m/s
s = ut + 1/2at^2
s = 12*2 + 1/2*(-6)*4
s = 24 + (-12)
s = 12m
Therefore, the distance travelled by car after the brakes are applied is 12m.
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