Question

find the hcf of the following numbers.

Answer 1

USING EUCLID DIVISION LEMMA 
A = BQ + R
(a)-(404,96)
step 1 - 404 = 96*4 + 20
step 2 - 96 = 20*4 + 16
step 3 - 20 = 16*1 + 4
step 4 - 16 = 4*4 + 0    r=0
therefore the HCF = 4
(b)- (336,54)
step 1 - 336 = 54*6 + 12
step 2 - 54 = 12*4 + 6
step 3 - 12 = 6*2 + 0   r = 0
therefore the HCF is 6
(c)- (65,117)
step 1 - 117 = 65*1 + 52
step 2 - 65 = 52*1 + 12
step 3 - 52 = 12*4 + 4
step 4 - 12 = 4*3 + 0        r=0
therefore the HCF is 4
(d)- (2520,405)
step 1 - 2520 = 405*6 + 90
step 2 - 405 = 90*4 + 45
step 3 - 90 = 45*2 + 0    r=0
therefore the HCF is 45

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