Question

Find the HCF of the following numbers by bi prime factorisation and continued division method 32 ,64,96,128

Answer 1

Step-by-step explanation:

2 | 32 2 | 64 2 | 96 2 | 128

2 | 16 2 | 32 2 | 48 2 | 64

2 | 8 2 | 16 2 | 24 2 | 32

2 | 4 2 | 8 2 | 12 2 | 16

2 | 2 2 | 4 2 | 6 2 | 8

| 1 2 | 2 3 | 3 2 | 4

| 1 | 1 2 | 2

| 1

32 = 2×2×2×2×2 = 2⁵

64 = 2×2×2×2×2×2 = 2⁶

96 = 2×2×2×2×2×3 = 2⁵×3

128 = 2×2×2×2×2×2×2 = 2⁷

HCF = 2

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