Question

find the HCF of the following numbers by prime factorisation method.
(a) 76, 28
(b) 24, 16, 36
(c) 38, 64, 82​

Answer 1

Answer:

a) $HCF(28,76)=4$

b) $HCF(16,24,36)=4$

c) $HCF(38, 64, 82)=2$

Step-by-step explanation:

To find : The HCF of the following numbers by prime factorization method ?

Solution :

HCF is the highest common factor.

a) 76, 28

$76=2\times 2\times 19$

$28=2\times 2\times 7$

$HCF(28,76)=2\times 2$

$HCF(28,76)=4$

b) 24,16,36

$16=2\times 2\times 2\times 2$

$24=2\times 2\times 2\times 3$

$36=2\times 2\times 3\times 3$

$HCF(16,24,36)=2\times 2$

$HCF(16,24,36)=4$

c) 38, 64, 82

$38=2\times 19$

$64=2\times 2\times 2\times 2\times 2\times 2$

$82=2\times 41$

$HCF(38, 64, 82)=2$

$HCF(38, 64, 82)=2$

Answer 2

Answer:

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