Question

find the HCF of the following numbers by using prime factors:
27,36 and 45​

Answer 1

Step-by-step explanation:

$27 = 3 \times 3 \times 3 \\ 36 =2 \times 2 \times 3 \times 3 \\ 45 = 3 \times 3 \times 5 \\ \\ HCF = 3 \times 3 = 9$