Question

find the HCF of the following pairs of integers by prime factorisation method
a)506&1155
b)1288&575

Answer 1

Hey there !

Lets do the prime factorization of the first set of numbers !

a)
506 = 2 x 11 x 23
1155 = 3 x 5 x 7 x 11

HCF = 11


b)
Prime factors of 575 = 52 x 23
Prime factors of 1288 = 23 x 7 x 23

HCF = 23

Answer 2

(a)hcf of 506 and 1155

506 = 2 x 11 x 23
1155 = 3 x 5 x 7 x 11

HCF is 11

b)hcf of 1288 and 575

575 = 52 x 23
1288 = 23 x 7 x 23

HCF is 23

Hope it helps