Question

FInd the HCF of x²y⁵ and x³y⁴

Answer 1

Step-by-step explanation:

From remainder theorem, we know that when a polynomial f(x) is divided by (x–a), then the remainder is f(a).

Given, f(x)=x

4

–3x

2

+2x+1 is divided by x–1

So, remainder =f(1)=(1)

4

–3(1)

2

+2(1)+1=1–3+2+1=1

Answer 2

$\large\fcolorbox{pink}{blue}{ANSWER}$

For HCF, we need to take the product of the smallest power of each common prime factors in the numbers.

Then,

Let y = x²y⁵ and z = x³y⁴

HCF(y, z) ➠ x²y⁴

Hope it wil help u