Math, asked by arjunpaudel337, 7 months ago

Find the HCF of x3-2x2-3x and x3-9x and x4-27x

Answers

Answered by Anonymous
1

Answer:

Step-by-step explanation:

HCF of ×3-2×2-3×

=×6-2-3×

=×4-3×

=×1

So ×1 is the HCF

x3-9x

Factors of 3 is 1,3

Factors of 8 is 1,3,9

HCF is ×3

x4-27x

Factors of ×4=1,2,4

Factors of 27× is 1,27

HCF is 1×

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