find the hcf of65 and117 and expressed it as a linear combination of 65 and 117 ie hcf of 65 and 117= 65x+117y
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HCF of 65 and 117 is :
117=65×1 +52. ....(i)
65 =52×1+13. .....(ii)
52 =13×4 +0. ....(iii)
Therefore, HCF is 13.
Expressing HCF as 65x + 117y :
13 = 65-52×1. -from (ii)
13= 65 -(117-65×1)×1. -from (i)
13 =65×1 -117×1 +65×1
13= 65×2 -117×1
13 =65 ×2 +117×-1
13 = 65(2)+ 117(-1)
13 =65x +117y
Therefore, x=2 & y=-1
Hope my answer helped you
tineshori:
thank you so much
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