find the HCF using prime factorisation method of 144 , 180 and 192
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This question had 192 too with 144 and 180. So here is the solution for that.
Factors of 144 = 2×2×2×2×3×3
Factors of 180 = 2×2×3×3×5
Factors of 192 = 2×2×2×2×2×2×3
Common factors of 144, 180, 192 = {2,2,3}
LCM (144,180,192) =
2×2×2×2×2×2×3×3×5 = 2880
So, HCF(144,180,192) = 2×2×3 = 12.
If there is any confusion please leave a comment below.
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