Question

Find the HCF
: x³-x²y and x²-y²

Answer 1

Answer:

Need to find HCF of x³-y³ and x²+xy+y²

The first one= x³-y³= (x-y)*(x²+xy+y²) and has 2 factors

The second one is equal to one of the factors of the first one.

So, the 2 above have common factor of x²+xy+y² which is the HCF

Answer 2

Answer:

x³-x²y=(x)(x)(x)

(x(x)