find the heat dissipated in 6 ohm coil in 1 min.
Answers
Step-by-step explanation:
The heat is denoted by H
and we know the formula
H=I^2rT, where r=resistance, i.e 6ohm, t=60 seconds, we need to find the current I flowing through that resistance.
we need to find total resistance first to do so
On the right part there are 3 resistances in series, namely 7ohm, 1ohm and 10ohm, equals 18ohm.
The resultant resistance is parallel with 6 ohm.
6x18/24=4.5ohm.
Now, 2ohm and 8ohm are in series with 4.5ohm.
so 14.5 resistance will be the equivalent resistance, i.e in series with 0.5 resistor so total resistance will be 15 resistance.
so I will be 1A(ampere)(I=v/r, you calculate)
so heat produced at 6 ohm resistor will be,
H=i^2rt
=rt(since square of 1 will be 1)
=6 x 60=360J , J stands for joule, you should know this.