Question

Find the heat energy produced in a resistor of 20 Ω when 4A current flows through it ,for 5 minutes. ​

Answer 1

$\purple{\boxed{\texttt{Answer}}}$

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Given:

I = 2.5A

R = 20Ω

t = 5×60 = 300 sec

Heat Produced = (Potential Difference) × (Current) × (time)

= V I t

= I²Rt °•° (ohm's law, V=IR)

= 25/10×25/10×20×300=37500J

= 37.5kJ

Hence,

$\red{\boxed{\texttt{37.5 kJ}}}$ heat is produced .

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Answer 2

Answer:

The heat energy produced in a resistor of 20 Ω when 4A current flows through it, for 5 minutes will be $96000\ J$

Explanation:

• Let H be the heat produced due to a flow of current given by the expression,

       $H = I^{2}R t$       ...(1)

• Where R is the resistance, A is the current flowing and t is the time of flow of current.

In the question, it is given that,

$R =20\Omega$         $I = 4 A$         $t = 5 min = 5\times 60 = 300\ s$

substitute these values into equation(1)

we get,

$H = 4^{2}\times 20\times 300=96000 J$