Question

find the heat generated in calories if a current of 0.2A is passed through a coil of resistance 418 ohm for 1 minutes​

Answer 1

Answer:

The power dissipated in the coil is P = I^2R = (0.3)^2 ٠ 418 = 37.62 watts = 37.62 joules/sec. In one minute, the amount of heat energy produced is E = P٠t = 37.62٠60 = 2257.2 joules = 2257.2 /4.184 calories = 539.48 calories.

Explanation:

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Answer 2

Answer:

The power dissipated in the coil is P = I^2R = (0.3)^2 ٠ 418 = 37.62 watts = 37.62 joules/sec. In one minute, the amount of heat energy produced is E = P٠t = 37.62٠60 = 2257.2 joules = 2257.2 /4.184 calories = 539.48 calories.

Explanation: