Science, asked by payalbari51, 11 months ago

Find the heat needed to raise the temperature of 100 g of a metal through 10 C IF THE SPECIFIC HEAT OF THE METAL IS 0.1 CAL /g. c solve​

Answers

Answered by BrainIyMSDhoni
33

What is heat capacity?

Heat capacity is the amount of heat required to be supplied to mass of a material in order to produce a unit change in its temperature is called as heat capacity. It is an extensive property.

While specific heat capacity is defined as the amount of heat energy in joules required to raise the temperature of 1 gram of a substance by temperature of 1 Kelvin.

The formula for specific heat capacity is :-

 \sf{Specific \: heat \: 'c' \: =  \frac{Q}{m} \: (T2 - T1)}

Now come to the Question:-

Given :-

Mass (m) = 100g

Temperature (T2-T1) = 10°C

Specific heat (c) = 0.1g/gram C°

Let the heat capacity be Q.

Therefore formula will be as

 \sf{c =  \frac{Q}{mT}} \\  \\ \sf{On \: Using \: the \: values} \\ \\ =  >  \sf{0.1 =  \frac{Q}{100g \times 10} } \\ \\ =  >  \sf{Q = 100 \times 10 \times 0.1} \\ \\ =  >  \sf{q = 100 \: calorie}

Hence:-

The heat capacity is 100 calories.

#answerwithquality #BAL

Answered by shreya7994
2

Answer:

What is heat capacity?

Heat capacity is the amount of heat required to be supplied to mass of a material in order to produce a unit change in its temperature is called as heat capacity. It is an extensive property.

While specific heat capacity is defined as the amount of heat energy in joules required to raise the temperature of 1 gram of a substance by temperature of 1 Kelvin.

The formula for specific heat capacity is :-

\sf{Specific \: heat \: 'c' \: = \frac{Q}{m} \: (T2 - T1)}Specificheat

c

=

m

Q

(T2−T1)

Now come to the Question:-

Given :-

Mass (m) = 100g

Temperature (T2-T1) = 10°C

Specific heat (c) = 0.1g/gram C°

Let the heat capacity be Q.

Therefore formula will be as

\begin{gathered}\sf{c = \frac{Q}{mT}} \\ \\ \sf{On \: Using \: the \: values} \\ \\ = > \sf{0.1 = \frac{Q}{100g \times 10} } \\ \\ = > \sf{Q = 100 \times 10 \times 0.1} \\ \\ = > \sf{q = 100 \: calorie}\end{gathered}

c=

mT

Q

OnUsingthevalues

=>0.1=

100g×10

Q

=>Q=100×10×0.1

=>q=100calorie

Hence:-

The heat capacity is 100 calories.

Explanation:

h

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