Question

Find the heat required to raise the temperature of 2g of water from 10 degree celcious to 40 degree celcious given C=4 .2 J1g degree celcious

Answer 1

Answer:

252 J

Explanation:

Use the equation

• Q = mS∆T

Where

• Q = Heat supplied
• m = Mass of substance
• S = Specific heat capacity of substance
• ∆T = Change in temperature of substance

Q = 2 g × 4.2 J/(g °C) × [40°C - 10°C]

= (2 × 4.2 × 30) J

= 252 J

Answer 2

Answer:

The heat required to raise the temperature of $2g$ of water from $10$ degree  celcious to $40$ degree is $252J$.

Explanation:

The body's thermal capacity, or heat capacity, is defined as the amount of heat necessary to raise a body's temperature by $1$ Kelvin.

The heat necessary to raise the temperature of a body by $1K$ and the heat required by the unit mass of a substance to raise the temperature by $1K$ are two separate terms. The heat capacity and specific heat capacity of these concepts differ.

The energy used to raise the temperature is referred to as heat.

$\mathrm{Q}=\mathrm{mS} \Delta \mathrm{T}$

where $Q$ is the heat in joules

$T$ is the temperature in Kelvin.

$m =$ Mass of substance

$S =$Specific heat capacity of substance

$\Delta \mathrm{T}=$Change in temperature of substance

$\begin{aligned}&Q=2 \mathrm{~g} \times 4.2 \mathrm{~J} /\left(\mathrm{g}^{\circ} \mathrm{C}\right) \times\left[40^{\circ} \mathrm{C}-10^{\circ} \mathrm{C}\right] \\&=(2 \times 4.2 \times 30) \mathrm{J} \\&=252 \mathrm{~J}\end{aligned}$

The heat required to raise the temperature $252J$.