Question

Find the height at which acceleration due to gravity becomes 1/4 th of it value on the surface of the earth/

Answer 1

Answer:

Height equal to radius of the earth .

Explanation:

g' = GM/(R+h)^2

g = GM/R^2

g' = g/4

GM/(R+h)^2 = GM/4 R^2

4R^2 = (R+h)^2

2R = R + h

R = h