Find the least value of n for which 1 + 7 + 7^2 + ... + 7^n > 1000.
Answers
Answer:
Step-by-step explanation:
5n+7=7 (n+1)-2n
Simplifying
5n + 7 = 7(n + 1) + -2n
Reorder the terms:
7 + 5n = 7(n + 1) + -2n
Reorder the terms:
7 + 5n = 7(1 + n) + -2n
7 + 5n = (1 * 7 + n * 7) + -2n
7 + 5n = (7 + 7n) + -2n
Combine like terms: 7n + -2n = 5n
7 + 5n = 7 + 5n
Add '-7' to each side of the equation.
7 + -7 + 5n = 7 + -7 + 5n
Combine like terms: 7 + -7 = 0
0 + 5n = 7 + -7 + 5n
5n = 7 + -7 + 5n
Combine like terms: 7 + -7 = 0
5n = 0 + 5n
5n = 5n
Add '-5n' to each side of the equation.
5n + -5n = 5n + -5n
Combine like terms: 5n + -5n = 0
0 = 5n + -5n
Combine like terms: 5n + -5n = 0
0 = 0
Solving
0 = 0
Answer:
The least value of n is 5.
Step-by-step explanation:
Concept:-
Sum of n terms of GP,
Step 1 of 2
Consider the given inequality as follows:
. . . . . (1)
Rewrite the inequality (1) as follows:
⇒ . . . . . (2)
Notice that the left-hand side series is a geometric progression (GP) on n terms such that the first term, =
and common ratio, r = 7.
Simplify the left-hand side as follows:
Thus, the inequality (2) becomes,
Multiply both the sides by the number as follows:
⇒
⇒
Add the number 1 both the sides as follows:
⇒
⇒ . . . . (3)
Step 2 of 2
Substituting the values for in (3) to get the least value for .
For ,
⇒
⇒ 7 > 6001, which is not possible.
For ,
⇒
⇒ 49 > 6001, which is not possible.
For ,
⇒
⇒ 343 > 6001, which is not possible.
For ,
⇒
⇒ 2401 > 6001, which is not possible.
For ,
⇒
⇒ 16807 > 6001, which is true.
Therefore, the least value of n for which the given inequality holds is 5.
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