Question

Find the height of a cylinder whose height volume is 1.54m^3 and diameter of the base is 140 cm

Answer 1

Step-by-step explanation:

$volume \: of \: cylinder = \pi \: {r}^{2} h \\ \therefore \: 1.54 \times {10}^{6} = \frac{22}{7} \times {(70)}^{2} \times h \\ \therefore \: h = \frac{1.54 \times {10}^{6} \times 7}{22 \times 4900} \\ \therefore \: h = \frac{0.7 \times 1000000 \times 7}{4900} \\ \therefore \: h = \frac{49 \times 100000 }{4900} \\ \therefore \: h = \frac{4900000}{4900} \\ \therefore \: h = 1000 \: cm \: \\ \huge \: \fbox{\therefore \: h = 10 \: m}$

Answer 2

Given,

• Volume of cylinder = 1.54 m ³
• and diameter of cylinder = 140 cm

Radius (r) = $\frac{d}{2}=\frac{140}{2}$=70 cm

Volume of cylinder = πr²h

$⇒ 1.54 = \frac{22}{7} \times 0.7 \times 0.7 \times h$

After simplifying, we get the value of h that is

$h = \frac{1.54 \times 7}{22 \times 0.7 \times 0.7}$

$⇒ h = 1$

Hence, height of the cylinder is 1 m.