Find the height of a cylinder with a radius of 21 cm and a curved surface area of 3960 cm².
Answers
Required Solution :
Given:
• Base radius of the cylinder (r) = 21 cm
• C.S.A of cylinder = 3960 cm²
To calculate:
• Height of the cylinder (h) = ?
Calculation:
Here, we are given the radius and C.S.A of the cylinder. By making a suitable equation through the formula of C.S.A, we can find its height.
Let the height of the cylinder be h.
As we know that,
★
Substituting values:
→
→
→
→
→
→
→
→
→
Hence, height of the cylinder is 30 cm.
_______________________________
More Formulae:
● Volume of the cylinder = πr²h
● C.S.A of the cylinder = 2πrh
● T.S.A of the cylinder = 2πr(h+r)
✓Verified Answer
Required Solution :
Given:
• Base radius of the cylinder (r) = 21 cm
• C.S.A of cylinder = 3960 cm²
To calculate:
• Height of the cylinder (h) = ?
Calculation:
Here, we are given the radius and C.S.A of the cylinder. By making a suitable equation through the formula of C.S.A, we can find its height.
Let the height of the cylinder be h.
As we know that,
★\boxed{\sf{{C.S.A}_{(Cylinder)}=(2 \pi rh)sq \: units }}
C.S.A
(Cylinder)
=(2πrh)squnits
Substituting values:
→ \sf {3960 \: {cm}^{2} =(2 \times \dfrac{22}{7} \times 21 \times h) \: {cm}^{2} }3960cm
2
=(2×
7
22
×21×h)cm
2
→ \sf {3960 \: {cm}^{2} =(2 \times 22 \times 3 \times h) \: {cm}^{2} }3960cm
2
=(2×22×3×h)cm
2
→ \sf {3960 \: {cm}^{2} =(44 \times 3 \times h) \: {cm}^{2} }3960cm
2
=(44×3×h)cm
2
→ \sf {3960 \: {cm}^{2} =(132 \times h) \: {cm}^{2} }3960cm
2
=(132×h)cm
2
→ \sf {3960 \: {cm}^{2} =132h \: {cm}^{2} }3960cm
2
=132hcm
2
→ \sf {\dfrac{3960}{132} cm = h \: cm }
132
3960
cm=hcm
→ \sf {\dfrac{1980}{66} cm = h \: cm }
66
1980
cm=hcm
→ \sf {\dfrac{990}{33} cm = h \: cm }
33
990
cm=hcm
→ \sf \red {30 cm = h \: cm }30cm=hcm
Hence, height of the cylinder is 30 cm.
_______________________________
More Formulae:
● Volume of the cylinder = πr²h
● C.S.A of the cylinder = 2πrh
● T.S.A of the cylinder = 2πr(h+r)