Question

Find the height of a right angle of area 106 cm sq. and base 20 cm.​

Answer 1

$\huge{\red{\boxed{\purple{\boxed{\blue{\boxed{\green{\boxed{\orange{\boxed{\red{\boxed{\underbrace{\mathcal{\pink{A}\orange{n}\blue{S}\red{w}\green{E}\purple{R}}}}}}}}}}}}}}}}$

$area \: \: \: of \: \: \: a \: \: \: triangle \: \: \: = \: \: \: \frac{1}{2} \times b \times h \\ \\ 106 = \frac{1}{2} \times 20 \times h \\ \\ \frac{106 \times 2}{20} = h \\ \\ 10.6 = h$

$\huge{\red{\boxed{\orange{h = 10.6}}}}$

Answer 2

Answer:

$\huge {\bf {\underline {given}}}$

• Area of right angled triangle = 106 cm²
• Base of right angled triangle = 20 c

$\huge {\bf {\underline {to \: find}}}$

Height of triangle

$\huge {\bf {\underline {solution}}}$

As we know that

$\huge \bf \: area \: = \frac{1}{2} \times b \times h$

Let the height be h

$106 = \frac{1}{2} \times 20 \times h$

$\frac{106 \times 2}{20}$

$1</u><u>0</u><u>.</u><u>6</u><u> </u><u>cm</u><u>$