find the height of a trapezium, the sum of lengths of whose base is 26 cm whose area is 65 cm
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Answered by
7
Answer:
Given that,
Length of bases of trapezium = 13 cm and 26 cm
Area = 65 cm2
We know that,
Area of trapezium = 1/2
(Sum of lengths of parallel sides) × altitude 65 = 1/2 (13 + 26) × altitude 65 = 39/2 × altitude
Which implies, altitude = (65×2) /39 = 130/39 = 10/3
∴ Length of altitude = 10/3 cm
Answered by
1
According to me 10/3 cm is the answer
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