find the height of a trapezium whose area is 1080cm square and lengths of its parallel sides are 55.6cm and 34.4 cm
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Answered by
12
area=1/2h(a+b)
1080=1/2h(55.6+34.4)
1080=1/2h(90)
h=1080×2/90
h=108×2/9
h=12×2
h=24cm is answer
1080=1/2h(55.6+34.4)
1080=1/2h(90)
h=1080×2/90
h=108×2/9
h=12×2
h=24cm is answer
kamlesh1466:
nice
Answered by
12
given area of trapezium = 1080 cm^2
1/ 2( sum of parallel sides )× h = 1080
1 / 2( 55 .6 + 34.4 ) × h = 1080
90h = 2160
h = 2160 / 90
h = 24 cm
hence ,the height of trapezium = 24cm
1/ 2( sum of parallel sides )× h = 1080
1 / 2( 55 .6 + 34.4 ) × h = 1080
90h = 2160
h = 2160 / 90
h = 24 cm
hence ,the height of trapezium = 24cm
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