Question

Find the height of a triangle , if it’s area is 87 sq cm and base is 15 cm

Answer 1

Given,

• area — 87 cm²
• base — 15 cm

To find:

the area of triagnle.

${ \rm{area = \dfrac{1}{2} \times base \times height}}$

${ \rm{ \implies \: 87= \: \dfrac{1}{2} \times 15 \times height}}$

${ \rm{ \implies \: 87= \: \dfrac{1}{2} \times 15 \times height}}$

${ \rm{ \implies \: h= \: \dfrac{1 \times 15}{2 \times 87} }}$

${ \rm{ \implies \: h= 652.5 }}$

${ \rm{ \implies \therefore h= 652.5 }}$

Answer 2

Given,

area — 87 cm²

base — 15 cm

To find:

the area of triagnle.

{ \rm{area = \dfrac{1}{2} \times base \times height}}area=

2

1

×base×height

{ \rm{ \implies \: 87= \: \dfrac{1}{2} \times 15 \times height}}⟹87=

2

1

×15×height

{ \rm{ \implies \: 87= \: \dfrac{1}{2} \times 15 \times height}}⟹87=

2

1

×15×height

{ \rm{ \implies \: h= \: \dfrac{1 \times 15}{2 \times 87} }}⟹h=

2×87

1×15

{ \rm{ \implies \: h= 652.5 }}⟹h=652.5

{ \rm{ \implies \therefore h= 652.5 }}⟹∴h=652.5