Question

Find the height of a triangle whose area is 24 - 32a square units and base is a units
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Answer 1

Answer:

$h =\frac{48 - 64a^2}{a} \:units$

Step-by-step explanation:

$\frac{1}{2} bh = 24-32a^2\\\\\frac{1}{2} (a)(h) = 24-32a^2\\\\h = \frac{2(24-32a^2)}{a}\\\\h =\frac{48 - 64a^2}{a} \:units$

Answer 2

Step-by-step explanation:

Answer:

h =\frac{48 - 64a^2}{a} \:unitsh=

a

48−64a

2

units

Step-by-step explanation:

\begin{gathered}\frac{1}{2} bh = 24-32a^2\\\\\frac{1}{2} (a)(h) = 24-32a^2\\\\h = \frac{2(24-32a^2)}{a}\\\\h =\frac{48 - 64a^2}{a} \:units\end{gathered}

2

1

bh=24−32a

2

2

1

(a)(h)=24−32a

2

h=

a

2(24−32a

2

)

h=

a

48−64a

2

units