find the height of an equilateral triangle whose side is 12
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area of equilateral ∆= √3/4 a²
=√3/4×12×12
36√3 unit²
again area of ∆=1/2×b×h
36√3=1/2×12×h
h=6√3
h=6×1.73
h=10.38 unit
=√3/4×12×12
36√3 unit²
again area of ∆=1/2×b×h
36√3=1/2×12×h
h=6√3
h=6×1.73
h=10.38 unit
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The answer is 6√3
Draw or construct the height of the triangle
Since it is an equilateral triangle, the height and the median are the same
Therefore, the base is divided into 2 equal parts
Take one of the right angled triangle and apply Pythagoras theorem
12^2 - 6^2 = 6√3
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