Question

Find the height of the parallelogram whose base is 15.4 cm and area of parallelogram is 16.38 sq. cm.
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Answer 1

☆☆ Question:- ☆☆

✵ find the height of the parallelogram whose base is 15.4 cm and area of parallelogram is 16.38² CM

✫✫ solution:-

☼︎height = 1.06

☼︎let's find out!!

✍︎✍︎we have:-

• base= 15.4cm
• height = h
• area = 16.38²cm

✫✫ by using formula:-

✵✵area of parallelogram :-

$\bold\blue{➪base \times height = area}$

$\bold\pink{➪15.4\times h = 16.38 {cm}^{2} }$

$\bold\green{➪ h = \frac{16.38}{15.4} }$

$\bold\orange{➪ h = 1.06cm}$

★★★ hence the height of the parallelogram is 1.06cm.

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★★what we should to learn:-★★

• area of rectangle = (l×b)

• area of square = (sides)²

• area of triangle = ½×b×h

• area of parallelogram = (b×h)

• area of rhombus = ½×d1×d2

• area of trapezium= ½ h (a+b)

• area of circle = πr²

• perimeter of rectangle = 2(l+b)

• perimeter of square = 4(side)

• circumference of circle = 2πr

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Answer 2

Step-by-step explanation:

‌$\huge{\underline{\bold{\blue{Question:⤵}}}}$

Find the height of the parallelogram whose base is 15.4 cm and area of parallelogram is 16.38 cm².

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‌$\huge{\underline{\bold{\red{Answer:⤵}}}}$

⋆➠Height = 1.06

⋆➠We have:-

base= 15.4cm

height = h

area = 16.38²cm

⋆➠ By using formula:-

Area of parallelogram :-

– Base x Height = Area

– 15.4 x h = 16.38 cm²

– h= 16.38/ 15.4

– h = 1.06 cm

Hence , the height of the parallelogram is 1.06cm.

⋆➠Learn More–

Area of Rectangle = (l×b)

Area of Square = (sides)²

Area of Triangle = ½×b×h

Area of Parallelogram = (b×h)

Area of Rhombus = ½×d1×d2

Area of Trapezium= ½ h (a+b)

Area of Circle = πr²

Perimeter of Rectangle = 2(l+b)

Perimeter of Square = 4(side)

Circumference of Circle = 2πr

$\bold\green{▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀}$