Question

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Answer 1

Question:

The value of $\sf{\sqrt{\sqrt{256}+\sqrt{81}}}$ is:

A. 5

B. 6

C. 7

D. 8

Analysis:

Square Root: A square root of a number is a value that, when multiplied by itself, gives the number.The symbol is √ which always means the positive square root.

In mathematics, a square root of a number x is a number y such that y² = x; in other words, a number y whose square is x.

Ex: For example, 4 and 4 are square roots of 16, because 4² = 4×4 = 16.

_____________________

Solution:

Given,

$→\;{\sf{\sqrt{\sqrt{256}+\sqrt{81}}}}$

$→\;{\sf{\sqrt{\sqrt{16²}+\sqrt{9²}}}}$

$→\;{\sf{\sqrt{16+9}}}$

$→\;{\sf{\sqrt{25}}}$

$→\;{\sf{\sqrt{5²}}}$

$➝\;{\bf{5}}$

AnSweR:

Value of $\sf{\sqrt{\sqrt{256}+\sqrt{81}}}$ is

◕➜ $\Large{{\red{\bf{Option\;A.}}}\;{\sf{5}}}$

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