Question

find the height of the trapezium the sum of the lengths of whose bases is 50 cm and whose area is 500 CM square

Answer 1

heya...

Here is your answer...

Given,

Lengths of the bases of trapezium = 50cm

Area of trapezium = 500cm

Height of trapezium = ?

Area of trapezium = 1/2×(a+b) × h

500 = 1/2×(50)×h

500 = 25×h

500/25 = h

100/5 = h

20=h

Therefore the height of the trapezium is 20cm.

It may help you...☺☺

Answer 2

$\tt \large AHOY!!! \:$

$\sf ATQ, \: the \: sum \: of \: the \: length \: of \: bases \: \\ \sf of \: the \: trapezium \: is \: 50cm. \: (\parallel sides )\\ \\ \sf and \: the \: area \: of \: the \: trapezium \: is \\ \sf given = {500cm}^{2} \\ \\ \sf now \: we \: have \: to \: find \: the \: height \: of \\ \sf the \: trapezium. \\ \\ \sf formula \: for \: the \: area \: of \: a \: trapezium \\ \sf is \: \frac{1}{2} h(b1 + b2) \: where \: b1 \: and \: b2 \: are \: \\ \sf the \: parallel \: sides \: and \: h \: is \: the \: height \\ \sf of \: the \: trapezium. \\ \\ \sf \therefore \: \frac{1}{2} h(b1 + b2) = 500 {cm}^{2} \\ \\ \sf > > \frac{1}{ \cancel2} h( \cancel{50}) = 500 {cm}^{2} \\ \\ \sf > > 25h = 500 {cm}^{2} \\ \\ > > \sf h = \frac{500}{25} \\ \\ > > \sf h = \boxed{20cm}$


hence, the height of the trapezium is 20cm.

$\tt \large HOPE \: IT \: HELPS!!$