Question

find the height of trapezium if area is 80cm2 and parllel sides are 11 cm and 9 cm​

Answer 1

To Find:-

• Find the height of the trapezium.

Given:-

• Area of trapezium is 80cm² , the length of parallel side is 11 cm and breadth is 9 cm.

Solution:-

️ ➭ Area = 1/2 (a + b) h

️ ➭ 80 = 1/2 ( 11 + 9 ) h

️ ➭ 80 = 10h

️ ➭ h = 80/10

️ ➭ $\tt \boxed { \: h \: = \: 8 cm \: }$

Verification:-

️ ➭ 80 = 1/2 ( 11 + 9 ) 8

️ ➭ 80 = 1/2 ( 20 × 8 )

️ ➭ 80 = 160/2

️ ➭ 80 = 80

Answer 2

$\\ \large\mathfrak {\underline \purple{ \: \: \: \: \: \: \: \: concept \: \: \: \: \: \: \: \: }} \\ \\ \\ \sf \: here \: in \: this \: query ,\: the \: question \: says \: that \\ \sf \: the \: area \: is \: given \: as \: \red{ 80cm {}^{2} } \\ \sf \: and \: the \: parallel \: sides \: are \: given \: as\: \red{11 \: cm }\: and \: \red{ 9 \: cm} \: \\ \sf \: we \: will \: take \: the \: parallel \: sides \: as \: a \: and \: b \: where \\ \sf \: a \: \longrightarrow \: 11 \: cm \: \\ \sf \: b \longrightarrow \: 9 \: cm \: \\ \sf \: we \: have \: to \: find \: the \: height \: here \\ \sf \: so \: we \: will \: apply \: this \: formula \: \\ \\ \bigstar {\underline {\boxed { \bf {\green\:area of \: the \: trapezium \: = \frac{1}{2} (sum \: of \: the \: parallel \: sides) \times height }}}}\bigstar$

$\\ \large\mathfrak {\underline \purple{ \: \: \: \: \: \: \: \: solution\: \: \: \: \: \: \: \: }} \\ \\ \\ \bigstar {\underline {\boxed { \bf {\green\:area of \: the \: trapezium \: = \frac{1}{2} (sum \: of \: the \: parallel \: sides) \times height}}}} \bigstar \\ \\ \bf \longrightarrow \: 80 = \frac{1}{2} (11 + 9) \times h \\ \\ \bf\longrightarrow \: 80 = \frac{1} {\cancel{2} } \times \cancel{20} \times h \\ \\ \bf \longrightarrow80 = 10 \times h \\ \\ \bf\longrightarrow10 \times h = 80 \\ \\ \bf \longrightarrow \: h = \frac{8 \cancel0}{1 \cancel0} \\ \\ \bf \longrightarrow \: h = 8 \: cm$

$\\ \\ \sf \therefore \: the \: height \: of \: the \: trapezium \: is \: 8 \: cm$

$\\ \bigstar{ \underline{ \underline \pink{ \sf★@iTzShInNy☆}}} \bigstar$