find the height pf a trapezuim, the sum of lengths of whose base is 39 cm and whose area is 65cm^2
Answers
Answered by
1
Solution :
Let a , b are two parallel
sides of the trapezium,
a + b = 39 cm [ given ]
Let height = h cm
Area = 65 cm² [ given ]
=> [ (a+b)h]/2 = 65
=> 39 × h = 130
=> h = 10/3 cm
Therefore ,
height ( h ) = 10/3 cm
= 3.33 cm
••••
Let a , b are two parallel
sides of the trapezium,
a + b = 39 cm [ given ]
Let height = h cm
Area = 65 cm² [ given ]
=> [ (a+b)h]/2 = 65
=> 39 × h = 130
=> h = 10/3 cm
Therefore ,
height ( h ) = 10/3 cm
= 3.33 cm
••••
mastermind31:
But this is not the correct answer
Similar questions