Question

find the highest common factor of the following




pls guys some help​

Answer 1

Given :

1. $\sf{18x^2 y^3, 20x^3 y^4,16x^2 y^2 }$
2. $\sf{12x^2 y,15xy^2, 18x^2 y^2}$

Explanation :

• Highest common factor (HCF) of the terms can be found by spitting the terms into prime factors of the term and selecting the common values in all the terms for once.
• For example if there are one a in first term , two a in the second term and five a in the third term the HCF of three terms will be one a.

Solution :

1. $\sf{18x^2 y^3, 20x^3 y^4,16x^2 y^2 }$

$\sf{18x^2 y^3}\Rightarrow \displaystyle{2\times 2\times \times 3 \times x\times x \times y \times y\times y}$

$\sf{20x^3 y^4}\Rightarrow \displaystyle {2\times 2\times 5 \times x\times x \times x \times y\times y\times y\times y}$

$\sf{16x^2 y^2}\Rightarrow \displaystyle {2\times 2\times 2\times 2\times x\times x \times y\times y}$

$\implies \sf{2\times 2\times x \times x \times y\times y}$

$\boxed{\boxed{\sf{4x^2 y^2}}}$

2. $\sf{12x^2 y,15xy^2, 18x^2 y^2}$

$\sf{12x^2 y}\Rightarrow 2\times 2\times 3\times x\times \times x \times y$

$\sf{15xy^2 }\Rightarrow \displaystyle {3\times 5\times x\times y\times y }$

$\sf{18x^2 y}\Rightarrow 2\times 3\times 3\times x \times x \times y\times y$

$\implies \sf{3 \times x \times y}$

$\boxed{\boxed{\sf{3xy}}}$

Required Answer :

1. HCF of$\sf{\:18x^2 y^3, 20x^3 y^4,16x^2 y^2 }$is ${\underline{\sf{4x^2 y^2}}}$

2. HCF of$\sf{\:12x^2 y,15xy^2, 18x^2 y^2}$is ${\underline{\sf{3xy}}}$

Answer 2

Answer:

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Step-by-step explanation:

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