Question

Find the hight of a right triangle whose hypotenuse is 25 cm and base is 6cm

Answer 1

$given -$


hypotenuse -25
base-6

$to \: find -$


hight of right angled triangle (p)

$we \: know \: that -$
${h}^{2} = {p}^{2} + {b}^{2}$
${25}^{2} = {p}^{2} + {6}^{2} \\ 625 = {p}^{2} + 36 \\ 625 - 36 = {p}^{2} \\ {p}^{2} = 589 \\ p = \sqrt{589 } \\ p = 24.26$

so, hight=24.26

Answer 2

The base of a hypotenuse of a right triangle are respectively 6cm and 10cm long. What is its area?

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6 ANSWERS



Aryaman Sharma

Answered Aug 22, 2018

By using Pythagoras property, we get

(6)^2 + (x)^2 = (10)^2

36 + (x)^2 = 100

x = (100 - 36)^1/2

x = (64)^1/2

x = 8 cm

Since the sides form a Pythagorean triplet

[(6)^2 + (8)^2] = (10)^2 ,

Therefore we can use 1/2*b*h where b = base and h = height .

Area of the triangle = 1/2*6*8

Area of the triangle = 3*8

Area of the triangle = 24 cm^2