Question

find the hight of the trapezium, and whose area is 65cm square cm and bases are 13 cm and 26 cm. answers in datail

Answer 1

Area of trapezium is given by
A = 1/2(Sum of parallel sides)×h

A/q
A = 65 sq. cm
Sum of Bases (or parallel sides) = 13 cm + 26 cm = 39 cm
h = ?

65 = 1/2(39)×h
130 = 39 ×h
h = 130/39
h = 10/3 cm

If expressed in mixed fraction

$\frac{10}{3} = 3\frac{1}{3}$

$h = \frac{10}{3}\: cm = 3\frac{1}{3}\: cm = 3.34\: cm$

All of the three above is the answer