Question

Find the horizontal force and the force inclined at 30° to the vertical, whose resultant is a vertical force P N. ​

Answer 1

$\huge\sf\orange{Answer\to}$

$pj = {f}^{1} i + ( - {f}^{2} cos \: 30 \: i + {f}^{2} sin \: 30j)$

Equating the coefficient of i and j, we get

${f}^{1} - {f}^{2} . \frac{ \sqrt{3} }{2} = 0 \: and \: {f}^{2} . \frac{1}{2} = p.$

${f}^{2} = 2p \: and \: {f}^{1} = \sqrt{3} p$