Question

Find the hypotenuse of a right-angled triangle having perpendicular sides of 7 cm and 24 cm




need answers fast


please help if you know


offering more points

​

Answer 1

Answer:

Right angled triangle hypotenuse

Therefore, if the given triangle is right angled triangle. Then we can find it out by Pythagoras theorem

Pythagoras theorem = (hypotenuse)²= (base)²+ (height)²

Let us consider that the given right angled triangle is ∆ABC

(AB)²= (AC)²+(BC)²

(AB)²= (7)²+ (24)²

(AB)²= 49+ 576

(AB)²= 625

AB = √625

AB= 25

Therefore, measure of hypotenuse is 25 cm.

THANK YOU!

DO MARK ME AS BRAINLIEST IF IT HELPS YOU!

Answer 2

Appropriate Question-:

• Find the hypotenuse of a right-angled triangle whose perpendicular side is of 7 cm and Base is of 24 cm .

AnswEr-:

• $\underline {\mathrm{\star{\red{ The\:Hypotenuse \:of\:Right \:Angled \:Triangle \:is\:25\:cm}}}}$

Explanation-:

$\mathrm {\bf{ Given -:}}$

• The Perpendicular of the Right angled triangle is 7 cm .

• The Base of the Right angled triangle is 24 cm .

$\mathrm {\bf{ To\:Find\: -:}}$

• The Hypotenuse of Right angled triangle.

$\mathrm {\bf{ \dag{ Solution \:of\:Question \:-:}}}$

• $\underbrace {\mathrm {\bf{ \underline { Understanding \:the\:Concept \:-:}}}}$

• We have to find Hypotenuse of Right angled triangle when Perpendicular and Base of Right angled triangle .

• As, We know that By Putting the given Values [ Perpendicular and Base ] in the Pythagoras theorem.

• By this, We can get the Hypotenuse of Right angled triangle.

____________________________________________

$\mathrm {\bf{ \dag{\underline {Finding\:Hypotenuse \:of\:Right \:Angled \:Triangle \:by\:Applying\:Pythagoras \:Theorem \:-:}}}}$

As , We know that ,

• $\underline{\boxed{\star{\sf{\blue{ Pythagoras \:Theorem\: = \: (Base)^{2} + (Perpendicular)^{2} =(Hypotenuse) ^{2} }}}}}$

$\mathrm {\bf{ Here -:}}$

• The Perpendicular of the Right angled triangle is 7 cm .

• The Base of the Right angled triangle is 24 cm .

Now , By Putting known Values in Pythagoras Theorem-:

• $\qquad \quad \qquad \quad \longmapsto{\mathrm { (7)^{2} + (24)^{2} = (Hypotenuse)^{2} }}$

• $\qquad \quad \qquad \quad \longmapsto{\mathrm { 49 + (24)^{2} = (Hypotenuse)^{2} }}$

• $\qquad \quad \qquad \quad \longmapsto{\mathrm { 49 + 576 = (Hypotenuse)^{2} }}$

• $\qquad \quad \qquad \quad \longmapsto{\mathrm { 625 = (Hypotenuse)^{2} }}$

Or ,

• $\qquad \quad \qquad \quad \longmapsto{\mathrm { (Hypotenuse)^{2} = 625 }}$

• $\qquad \quad \qquad \quad \longmapsto{\mathrm { Hypotenuse = \sqrt{625} }}$

• $\qquad \quad \qquad \quad \underline{\boxed{\mathrm{\pink { Hypotenuse = 25\:cm }}}}$

Hence,

• $\underline {\mathrm{\star{\red{ The\:Hypotenuse \:of\:Right \:Angled \:Triangle \:is\:25\:cm}}}}$

__________________________________________________

$\large { \boxed {\mathrm |\:\:{\underline {More \:To\:Know\:-:}}\:\:|}}$

• Pythagoras Theorem-: Pythagoras Theorem states that " In a Right angled triangle the sum of the square of Perpendicular and the square of the Base is always equal to the Square of Hypotenuse" .

• $\mathrm {\bf{ \dag{ Pythagoras \:Theorem\: = \: (Base)^{2} + (Perpendicular)^{2} =(Hypotenuse) ^{2} }}}$

___________________________________________________