Question

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Answer 1

Explanation:

f = {(1, 1), (2, 3), (0, –1), (–1, –3)} and f(x) = ax + b

(1, 1) ∈ f ⇒ f(1) = 1 ⇒ a × 1 + b = 1

⇒ a + b = 1

(0, –1) ∈ f ⇒ f(0) = –1 ⇒ a × 0 + b = –1

⇒ b = –1

On substituting b = –1 in a + b = 1,

We obtain a + (–1) = 1

⇒ a = 1 + 1 = 2.

Thus, the respective values of a and b are 2 and –1.

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