Question

find the hypotenuse of the base and perpendicular of 6 cm and 8 cm ​

Answer 1

In a right angled triangle Base = 8 cm,

perpendicular = 6 cm.

By Pythagorous theorem.

∵ (Hypotenuse)² = (Perp)² + (Base)²

(Hypotenuse)² = 62 + 82

⇒ (Hypotenuse)² =36 + 64.

⇒ (Hypotenuse)² = 100,

∴ Hypotenuse = √100 = 10 cm.

Answer 2

$\maltese\LARGE\textsf{\underline{ GiVeN :-}}$

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\large\textsf{Base of the triangle = 6cm}$

$\qquad\tt{:}\longrightarrow\large\textsf{Perpendicular of the triangle = 8cm}$

$\large\textsf{ }$

$\maltese\LARGE\textsf{\underline{ To FiNd :-}}$

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\large\textsf{Hypotenuse of the triangle = ?}$

$\large\textsf{ }$

$\maltese\LARGE\textsf{\underline{ FoRmUla :-}}$

$\large\textsf{ }$

$\large\texttt{ By Pythagoras Theorem :-}$

$\large\textsf{ }$

$\qquad\tt{}\boxed{\large\textsf\textcolor{purple}{Hypotheses ² = Perpendicular ² + Base²}}$

$\large\textsf{ }$

$\maltese\LARGE\textsf{\underline{ SoLuTioN :-}}$

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\large\textsf{Hypotenuse² = 6² + 8²}$

$\qquad\tt{:}\longrightarrow\large\textsf{= 36 + 64 }$

$\qquad\tt{:}\longrightarrow\large\textsf{Hypotenuse ² = 100}$

$\qquad\tt{}\therefore\boxed{\large\textsf\textcolor{red}{Hypotenuse = √100}}$