Math, asked by nirikumari41, 4 days ago

find the lowest natural number which when divided by 14,49,84 and 63 leaves a reminder 3 in each case​

Answers

Answered by anshulriyanshi
0

Answer:

591

Step-by-step explanation:

LCM of 14, 49, 84

2 | 14, 49, 84

7 | 7, 49, 42

7 | 1, 7, 6

6 | 1, 1, 6

   | 1, 1, 1

LCM = 6 × 7 × 7 × 2 = 588

When leaving remainder 3 in each case,

588 + 3 = 591

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