find the lowest natural number which when divided by 14,49,84 and 63 leaves a reminder 3 in each case
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Answer:
591
Step-by-step explanation:
LCM of 14, 49, 84
2 | 14, 49, 84
7 | 7, 49, 42
7 | 1, 7, 6
6 | 1, 1, 6
| 1, 1, 1
LCM = 6 × 7 × 7 × 2 = 588
When leaving remainder 3 in each case,
588 + 3 = 591
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