Math, asked by shivalingappaathani6, 4 months ago

find the image of (2, 3) in the line 3x+5y=4​

Answers

Answered by Flaunt
18

Given :

point (2,3) & line 3x+5y=4

To Find :

image of point (2,3) on the line 3x+5y=4

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Step by step explanation:

Let p(a,b) be the image of point (2,3) on the line 3x+5y=4

3x+5y=4.......(1)

Now \: Slope =  \frac{ - A}{B}  =  \frac{ - 3}{5}

AP ⟂BC

Slope \: of \: line \: AP= m2 =  \frac{ \frac{ - 1}{ - 3} }{5}  =  \frac{5}{3}

 \frac{b - 2}{a - 1}  =  \frac{5}{3}

 =  > 3b - 6 = 5a - 5

 =  > 5a - 3b =  - 1.....(2)

Now O is the midpoint of AP

Coordinate \: of \: O =  (\frac{a + 1}{2} )( \frac{b + 1}{2} )

Now put O's coordinate in equation 1

 =  > 3( \frac{a + 1}{2} ) + 5( \frac{b + 2}{2} ) - 4 = 0

 =  >  \frac{3a + 3 + 5b + 10 - 8}{2}  = 0

 =  > 3a + 5b + 5 = 0.....(3)

Now equating equation 2&3

we \: get \: a =   - \frac{10}{17} ,b =  -  \frac{11}{17}

Therefore ,image of point (2,3) on the line 3x+5y=4 is ( \bold{\red{-  \frac{10}{17}  ,-  \frac{11}{17}}} )

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