Question

solve the equation:-
Pleaseeeeee
3t+1/16-2t-3/7=t+3/8+3t-1/14​

Answer 1

Answer:

3t+1)/16-(2t-3)/7=(t+3)/8+(3t-1)/14

lcm of 16,7,8 and 14 is=112

multiply each term by 112

(3t+1)/16*112-(2t-3)7*112=(t+3)/8*112+(3t-1)/14*112

(3t+1)*7-(2t-3)16=(t+3)*14+(3t-1)*8

21t+7-32t+48=14t+42+24t-8

21t-32t-14t-24t=42-8-7-48

21t-70t=42-63

-49t=-21

t=21/49

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Given:-

• $\sf \dfrac{3t + 1}{16} - \dfrac{2t - 3}{7} = \dfrac{t + 3}{8} + \dfrac{3t - 1}{14}$

To Find:-

• The value of t

Solution:-

$\sf \dfrac{3t + 1}{16} - \dfrac{2t - 3}{7} = \dfrac{t + 3}{8} + \dfrac{3t - 1}{14}$

$\sf \implies \dfrac{7(3t + 1) - 16(2t - 3)}{112} = \dfrac{14(t + 3) + 8(3t - 1)}{112}$

$\sf \implies 21t + 7 - 32t + 48 = 14t + 42 + 24t - 8$

$\sf \implies 21t - 32t + 48 + 7 = 14t + 24t +42 - 8$

$\sf \implies - 11t + 55 = 38t + 34$

$\sf \implies 38t + 11t = 55 - 34$

$\sf \implies 49t = 21$

$\sf \implies t = \dfrac{21}{49}$

$\sf \implies t = \dfrac{3}{7}$

$\longrightarrow \underline{\boxed{\sf \therefore t = \frac{3}{7}}}$