find the image of point (1, -2, 3)in the plane 2x-3y+2z+3=0
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Explanation:
All planes intersect at straight lines, unless they're the same plane.
Which, if you divide that second equation by three on both sides, you'll see that they are indeed the same plane.
So no, they do not intersect at a line. They intersect at every point on the plane, since they are both the same plane.
So you can see the work:
(6/3)x - (3/3)y - (6/3)z + (9/3) = (0/3)
2x - y - 2z + 3 = 0
Which is the same as your first equation.
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