Question

Find the image of the point (-8,12) w.r.t the line mirror 4x+7y+13=0.?
No links please !! Experts please solve it.

Answer 1

the image of the point (-8,12) w.r.t the line mirror 4x+7y+13=0 is (-16,-2)

Answer 2

The image of the point (-8, 12) with respect to the line mirror 4x+7y+13=0 is (-10, -1).

To find the image of the point (-8,12) with respect to the line mirror 4x+7y+13=0,

We will use the formula for the reflection of a point over a line.

The formula for the reflection of a point (x, y) over a line Ax + By + C = 0 is given by:

$(x', y') = [(B^2 - A^2)x - 2ABy - 2Cx]/(A^2 + B^2), [(A^2 - B^2)y - 2ABx - 2Cy]/(A^2 + B^2)$

where $(x', y')$ is the reflected point.

In this case, the line mirror is 4x+7y+13=0,

so A=4, B=7 and C=13.

The point to be reflected is (-8, 12).

So, substituting these values in the formula, we get:

$x' = [(7^2 - 4^2)(-8) - 2(4)(7)(12) - 2(13)(7)] / (4^2 + 7^2) = -10$

$y' = [(4^2 - 7^2)(12) - 2(4)(7)(-8) - 2(13)(4)] / (4^2 + 7^2) = -1$

Therefore, the image of the point (-8, 12) with respect to the line mirror 4x+7y+13=0 is (-10, -1).

For similar question of image point line mirror

https://brainly.in/question/4184899

#SPJ3