Question

Find the incenter of the triangle formed by the following straight lines

(ii) x + y - 7 = 0, x- y + 1 = 0 and x - 3y + 5 = 0​

Answer 1

Answer:

Let AB be x+y = 7

BC be x-y +1 = 0

AC be x-3y +5 = 0

A is 4 ,3

B is 3, 4

C is 1 ,2

AB = c = √2

AC = b = √10

BC = a = 2√2

Incentre

Abcissa = 6√2 +3√10 / ( 3√2 +√10)

Oordinate = 5√2 + 4√10 / (3√2 +√10)

Step-by-step explanation:

Hope it's helpful.