Question

Find the incenter of triangle formed with vertices (1,√3),(0,0),(2,0)

Answer 1

${\huge {\mathfrak {Answer :-}}}$

➡️ The incenter of the vertices is,

= (x1 + x2 + x3)/3, (y1 + y2 + y3)/3

= (1 + 0 + 2)/3, ($\sqrt {3}$ + 0 + 0)/3

= 1, 1/$\sqrt {3}$

That's it..

Answer 2

Let the three vertices of a triangle be (1,√3),(0,0),(2,0),

and the coordinates of incenter be (x,y)

By Centroid Formula

x = (x1+x2+x3)/3

x = (1+0+2)/3

x = 3/3

x = 1

y = (y1+y2+y3)/3

y = (√3+0+0)/3

y = √3/3

y = 1/√3

Hence the co ordinates of incenter is (1,1/√3)

Hope it helps u ^_^ ^_^ ^_^

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