Find the incorrect trend for alkaline earth metals *
(a) atomic size Be < Mg < Ca < Sr
(b) second ionization energy Be < Mg < Ca < Sr
(c) Hydration enthalpy Sr < Ca < Mg < Be
(d) Density Ca < Mg < Be < Sr
Answers
The correct answer will be option b.
a)The atomic size increases as we go down a group because the number of shells keeps increasing.
Therefore, atomic size: Be < Mg < Ca < Sr
b)The second ionization energy is always greater than the first ionization energy for a given element. The smaller the size greater is the ionization energy.
second ionization energy: Be > Mg > Ca > Sr
c) As the ionic size increases the hydration enthalpy decreases.
Hydration enthalpy Sr < Ca < Mg < Be
d) As the volume of calcium is more it has a lower density than magnesium.
Density Ca < Mg < Be < Sr
Option b is the right response.
1. As we move down a group, the atomic size grows due to the growing number of shells.
As a result, atomic size: Be < Mg < Ca < Sr
2. For a particular element, the second ionization energy is always larger than the first ionization energy. The ionization energy increases as the size decreases.
Be > Mg > Ca > Sr is the second ionization energy.3.33
3.The hydration enthalpy reduces as the ionic size rises.
Sr Ca Mg Be Sr Ca Mg Be Sr Ca Mg Be Sr Ca Mg Be Sr Ca Mg Be Sr Ca Mg Be Sr Ca Mg Be Sr Ca
4. Calcium has a lower density than magnesium due to its larger volume.
Ca Mg Be Sr Density Ca Mg Be Sr