Math, asked by ashrafshazia885, 3 months ago

Pipe A takes 24 minute to fill a tank. Pipe B takes 32 minutes to fill the same
tank. If both the pipes are opened simultaneously, after how much time should
pipe A be closed so that it takes 16 minute to fill the tank.​

Answers

Answered by subhsamavartj
5

Step-by-step explanation:

Let the capacity of the tank be 96 L ( LCM of 24 & 32 ) .You can assume any other number which is a multiple of these two numbers.

Hence, rate of filling of water by tap A = 96 / 24 = 4 L/min,

Similarly, for B( rate of filling) = 96 / 32 = 3 L / min

Since A is open for 18 mins water filled by it = 18 *4 = 72 L

Water filled by B = 96 -72 = 24 L ,so the time for which it was open = 24 / 3 = 8 mins.

So, B must be closed after 8 mins for the tank to be filled in 18 mins.

Hope that helps !!!

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