Find the initial velocity of a car elwhich is stopped in 10 seconds by applying brakes. The retardation due to brakes is 2.5 m/s2
Answers
Answered by
1
v=0
a=-2.5m/s*s
t=10s
v=u+a*t
0=u+(-2.5)*10
0=u+(-25)
0+25=u
25=u
a=-2.5m/s*s
t=10s
v=u+a*t
0=u+(-2.5)*10
0=u+(-25)
0+25=u
25=u
Answered by
1
Question
Find the initial velocity of a car elwhich is stopped in 10 seconds by applying brakes. The retardation due to brakes is 2.5 m/s2
Answer
Time = 10 sec, Retardation = -2.5 m/s^2 and Final velocity = 0 m/s
v = u + at (First Equation Of Motion)
=> 0 = u + (-2.5)(10)
=> 0 = u - 25.0
=> -u = -25.0
=> u = 25 m/s
Similar questions