find the initial velocity of a car which is stopped in 10 seconds by applying breakes . The retardation due to brakes is 2•5m/s ?
Answers
Answered by
6
Let inital velocity of car = Vo
finally car comes to rest
so, final velocity ( Vf )= 0
use, kinematic equation ,
Vf = Vo + at
here, Vf = 0
a = -2.5 m/s²
t = 10 second
0 = Vo + (-2.5) × 10
Vo = 25 m/s
finally car comes to rest
so, final velocity ( Vf )= 0
use, kinematic equation ,
Vf = Vo + at
here, Vf = 0
a = -2.5 m/s²
t = 10 second
0 = Vo + (-2.5) × 10
Vo = 25 m/s
Answered by
3
Given :
v=0. (brakes)
a= -2.5m/s². (retardation)
t= 10sec
From first equation of motion
v= u+at
0= u+ (-2.5×10)
u-25=0
u= 25 m/sec
Hence the initial velocity is 25m/sec
v=0. (brakes)
a= -2.5m/s². (retardation)
t= 10sec
From first equation of motion
v= u+at
0= u+ (-2.5×10)
u-25=0
u= 25 m/sec
Hence the initial velocity is 25m/sec
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